Which one will not give alcohol on reduction | vedclass

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Question

(A) $LiAlH_4$ is a strong reducing agent. $CH_3CONH_2$ (amide) is reduced to $CH_3CH_2NH_2$ (amine),which is not an alcohol. $CH_3COCl$ (acid chloride

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$CH_3CONH_2$

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(A) $LiAlH_4$ is a strong reducing agent. $CH_3CONH_2$ (amide) is reduced to $CH_3CH_2NH_2$ (amine),which is not an alcohol. $CH_3COCl$ (acid chloride) is reduced to $CH_3CH_2OH$ (alcohol). $CH_3COOC_2H_5$ (ester) is reduced to $CH_3CH_2OH$ (alcohol) and $C_2H_5OH$ (alcohol). Therefore,$CH_3CONH_2$ does not give an alcohol upon reduction.

Which one will not give alcohol on reduction with $LiAlH_4$?

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