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Question

(B) The reaction of aniline $(C_6H_5NH_2)$ with sodium nitrite $(NaNO_2)$ and hydrochloric acid $(HCl)$ at a low temperature of $0-5\,^{\circ}C$ is kn

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Diazonium salt

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(B) The reaction of aniline $(C_6H_5NH_2)$ with sodium nitrite $(NaNO_2)$ and hydrochloric acid $(HCl)$ at a low temperature of $0-5\,^{\circ}C$ is known as the diazotization reaction.This reaction results in the formation of benzene diazonium chloride,which is a diazonium salt.The chemical equation is: $C_6H_5NH_2 + NaNO_2 + 2HCl \xrightarrow{0-5\,^{\circ}C} C_6H_5N_2^+Cl^- + NaCl + 2H_2O$.

When aniline is treated with sodium nitrite and hydrochloric acid at $0\,^{\circ}C$,it gives:

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