Which one of the following compounds can exis | vedclass

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(D) For geometrical isomerism $(GI)$ in alkenes,each carbon of the double bond must be attached to two different groups. For $GI$ in cycloalkanes,at l

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$1, 2-Dimethylcyclohexane$

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(D) For geometrical isomerism $(GI)$ in alkenes,each carbon of the double bond must be attached to two different groups. For $GI$ in cycloalkanes,at least two $sp^3$ carbons of the ring must each be attached to two different groups. $1.$ $Pent-1-ene$ $(CH_2=CH-CH_2-CH_2-CH_3)$: The terminal $CH_2$ group has two identical $H$ atoms,so it does not show $GI$. $2.$ $2-Methylhex-2-ene$ $((CH_3)_2C=CH-CH_2-CH_2-CH_3)$: The $C-2$ carbon has two identical $CH_3$ groups,so it does not show $GI$. $3.$ $1, 1-Dimethylcyclopropane$: The $C-1$ carbon has two identical $CH_3$ groups,so it does not show $GI$. $4.$ $1, 2-Dimethylcyclohexane$: Each of the two $sp^3$ carbons at positions $1$ and $2$ is attached to a $CH_3$ group and an $H$ atom (different groups),allowing for $cis$ and $trans$ configurations. Thus,$1, 2-Dimethylcyclohexane$ exhibits $cis-trans$ isomerism.

Which one of the following compounds can exist as $cis-trans$ isomers?

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