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(D) The given structure contains $3$ double bonds capable of showing geometrical isomerism (marked with asterisks in the image). Each double bond can

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$8$

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(D) The given structure contains $3$ double bonds capable of showing geometrical isomerism (marked with asterisks in the image). Each double bond can exist in either $E$ or $Z$ configuration. Since the molecule is unsymmetrical (the groups attached to the terminal double bonds are different),the total number of geometrical isomers is given by the formula $2^n$,where $n$ is the number of stereocenters. Here,$n = 3$. Therefore,the total number of geometrical isomers = $2^3 = 8$.

The number of geometrical isomers possible for the given structure is . . . . . . .

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