The incorrect statements regarding geometrica | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Analysis of the given statements:$(A)$ Propene $(CH_3-CH=CH_2)$ does not show geometrical isomerism because one of the doubly bonded carbons is at

Vedclass · Accepted Answer

$(A)$,$(D)$ and $(E)$ only

Vedclass · Answer

(A) Analysis of the given statements:$(A)$ Propene $(CH_3-CH=CH_2)$ does not show geometrical isomerism because one of the doubly bonded carbons is attached to two identical hydrogen atoms.$(B)$ This is a correct statement. In a trans isomer,identical groups are on opposite sides of the double bond.$(C)$ This is a correct statement. Cis$-$but$-2-$ene has a non-zero dipole moment due to the same side orientation of methyl groups,whereas trans$-$but$-2-$ene has a zero dipole moment due to symmetry.$(D)$ $2-$methylbut$-2-$ene $(CH_3-C(CH_3)=CH-CH_3)$ does not show geometrical isomerism because one of the doubly bonded carbons is attached to two identical methyl groups.$(E)$ This is an incorrect statement. Generally,the trans isomer has a higher melting point than the cis isomer due to better packing in the crystal lattice.Thus,the incorrect statements are $(A)$,$(D)$,and $(E)$.

Similar Questions

Which is the correct configuration of the given compound?

In the following structure,the double bonds are marked as $I$,$II$,$III$ and $IV$. Geometrical isomerism is not possible at site$(s)$:

Geometrical isomerism is shown by

The incorrect statement regarding the geometrical isomers of $2$-butene is:

Which of the following compounds will show $cis-trans$ isomerism?
$(i)$ $(CH_3)_2C=CH-C_2H_5$
$(ii)$ $CH_2=CBr_2$
$(iii)$ $C_6H_5CH=CH-CH_3$
$(iv)$ $CH_3CH=CClCH_3$

Vedclass Test Series

Exam Paper Generator

Online Exam Module