Which of the following relations is true for | vedclass

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(B) For two unit vectors $\hat{A}$ and $\hat{B}$ with angle $	heta$ between them:$|\hat{A}+\hat{B}| = \sqrt{|\hat{A}|^2 + |\hat{B}|^2 + 2|\hat{A}||\h

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$|\hat{A}-\hat{B}|=|\hat{A}+\hat{B}| 	an \frac{	heta}{2}$

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(B) For two unit vectors $\hat{A}$ and $\hat{B}$ with angle $	heta$ between them:$|\hat{A}+\hat{B}| = \sqrt{|\hat{A}|^2 + |\hat{B}|^2 + 2|\hat{A}||\hat{B}| \cos 	heta} = \sqrt{1+1+2 \cos 	heta} = \sqrt{2(1+\cos 	heta)} = \sqrt{2(2 \cos^2 \frac{	heta}{2})} = 2 \cos \frac{	heta}{2}$.$|\hat{A}-\hat{B}| = \sqrt{|\hat{A}|^2 + |\hat{B}|^2 - 2|\hat{A}||\hat{B}| \cos 	heta} = \sqrt{1+1-2 \cos 	heta} = \sqrt{2(1-\cos 	heta)} = \sqrt{2(2 \sin^2 \frac{	heta}{2})} = 2 \sin \frac{	heta}{2}$.Dividing the two magnitudes:$\frac{|\hat{A}-\hat{B}|}{|\hat{A}+\hat{B}|} = \frac{2 \sin \frac{	heta}{2}}{2 \cos \frac{	heta}{2}} = 	an \frac{	heta}{2}$.Therefore,$|\hat{A}-\hat{B}| = |\hat{A}+\hat{B}| 	an \frac{	heta}{2}$.

Which of the following relations is true for two unit vectors $\hat{A}$ and $\hat{B}$ making an angle $\theta$ to each other?

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