Where will it be profitable to purchase 1 kil | vedclass

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(B) The weight of an object is given by $W = mg$,where $m$ is the mass and $g$ is the acceleration due to gravity.Since the Earth is not a perfect sph

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At equator

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(B) The weight of an object is given by $W = mg$,where $m$ is the mass and $g$ is the acceleration due to gravity.Since the Earth is not a perfect sphere and bulges at the equator,the radius of the Earth is maximum at the equator and minimum at the poles.The acceleration due to gravity $g$ is inversely proportional to the square of the radius $(g \propto 1/R^2)$.Therefore,$g$ is minimum at the equator and maximum at the poles.To get more sugar for the same weight (or to pay less for the same mass),one should purchase where $g$ is minimum,as the balance will show a smaller weight for the same mass $m$.Thus,it is most profitable to purchase sugar at the equator.

Where will it be profitable to purchase $1$ kilogram of sugar?

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