Calculate the difference in the value of g at | vedclass

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(A) The acceleration due to gravity at the poles $(g_{p})$ is given by $g_{p} = G M / R^{2}$.At the equator,the effective acceleration due to gravity

Vedclass · Accepted Answer

$R_{e} \omega^{2}$

Vedclass · Answer

(A) The acceleration due to gravity at the poles $(g_{p})$ is given by $g_{p} = G M / R^{2}$.At the equator,the effective acceleration due to gravity $(g_{e})$ is given by $g_{e} = g - R_{e} \omega^{2}$,where $R_{e}$ is the radius of the Earth and $\omega$ is the angular velocity of the Earth's rotation.The difference in the value of $g$ between the poles and the equator is $\Delta g = g_{p} - g_{e}$.Substituting the expressions: $\Delta g = g - (g - R_{e} \omega^{2})$.Therefore,$\Delta g = R_{e} \omega^{2}$.

Calculate the difference in the value of $g$ at the equator and at the poles due to the rotation of the Earth.

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