When a potential difference V is applied acro | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The initial power dissipated is given by $W = \frac{V^2}{R} \quad ...(i)$When the wire is cut into two equal halves,the resistance of each half be

Vedclass · Accepted Answer

$4 W$

Vedclass · Answer

(D) The initial power dissipated is given by $W = \frac{V^2}{R} \quad ...(i)$When the wire is cut into two equal halves,the resistance of each half becomes $R' = \frac{R}{2}$.When these two halves are connected in parallel,the equivalent resistance $R_{eq}$ is given by:$\frac{1}{R_{eq}} = \frac{1}{R'} + \frac{1}{R'} = \frac{2}{R} + \frac{2}{R} = \frac{4}{R}$So,$R_{eq} = \frac{R}{4}$.The new power dissipation $W'$ with the same potential difference $V$ is:$W' = \frac{V^2}{R_{eq}} = \frac{V^2}{R/4} = 4 \left( \frac{V^2}{R} \right)$Substituting equation $(i)$ into this expression,we get:$W' = 4W$.

When a potential difference $V$ is applied across a wire of resistance $R$,it dissipates energy at a rate $W$. If the wire is cut into two halves and these halves are connected in parallel across the same supply,the energy dissipation rate will become:

Similar Questions

In the given circuit,the reading of the ideal voltmeter is $\frac{E}{2}$. Find the internal resistance $r$ of the cell in $\Omega$.

Each of the resistances in the network shown in the figure is equal to $R$. The resistance between the terminals $A$ and $B$ is

Considering the following circuit,select the correct alternative.

The resistance between the terminal points $A$ and $B$ of the given infinitely long circuit will be

When a resistor of $11 \Omega$ is connected in series with an electric cell,the current flowing in it is $0.5 \ A$. Instead,when a resistor of $5 \Omega$ is connected to the same electric cell in series,the current increases by $0.4 \ A$. The internal resistance of the cell is (in $Omega$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module