A 500, W heating unit is designed to operate | vedclass

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Question

${P_{consumed}} = {\left( {\frac{{{V_A}}}{{{V_R}}}} ight)^2} 	imes {P_R} = {\left( {\frac{{110}}{{115}}} ight)^2} 	imes 500 = 457.46\,\,W$

So

Vedclass · Accepted Answer

$8.6$

Vedclass · Answer

${P_{consumed}} = {\left( {\frac{{{V_A}}}{{{V_R}}}} ight)^2} 	imes {P_R} = {\left( {\frac{{110}}{{115}}} ight)^2} 	imes 500 = 457.46\,\,W$

So, percentage drop in power output

$ = \frac{{(500 - 457.46)}}{{500}} 	imes 100 = 8.6\,\% $

A $500\, W$ heating unit is designed to operate from a $115\, volt$ line. If the line voltage drops to $110\, volt$, the percentage drop in heat output will be ............... $\%$

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