A 220, volt, 1000, W bulb is connected across | vedclass

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Question

$\frac{{{P_1}}}{{{P_2}}} = {\left( {\frac{{{V_1}}}{{{V_2}}}} \right)^2}$$ \Rightarrow \frac{{1000}}{{{P_2}}} = {\left( {\frac{{220}}{{110}}} \right)^2

Vedclass · Accepted Answer

$250$

Vedclass · Answer

$\frac{{{P_1}}}{{{P_2}}} = {\left( {\frac{{{V_1}}}{{{V_2}}}} \right)^2}$$ \Rightarrow \frac{{1000}}{{{P_2}}} = {\left( {\frac{{220}}{{110}}} \right)^2} = 4$$ \Rightarrow $ ${P_2} = 250\,W$

A $220\, volt$, $1000\, W$ bulb is connected across a $110\, volt$ mains supply. The power consumed will be ............ $W$

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