What would be the C.I. obtained on an amount | vedclass

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(A) The formula for Compound Interest $(C.I.)$ is given by: $C.I. = P \left[ \left( 1 + \frac{R}{100} \right)^n - 1 \right]$ Given: Principal $(P)$ =

Vedclass · Accepted Answer

$3180$

Vedclass · Answer

(A) The formula for Compound Interest $(C.I.)$ is given by: $C.I. = P \left[ \left( 1 + \frac{R}{100} ight)^n - 1 ight]$ Given: Principal $(P)$ = $12500$ Rate $(R)$ = $12 \, p.c.p.a.$ Time $(n)$ = $2 \, 	ext{years}$ Substituting the values: $C.I. = 12500 \left[ \left( 1 + \frac{12}{100} ight)^2 - 1 ight]$ $C.I. = 12500 \left[ (1.12)^2 - 1 ight]$ $C.I. = 12500 \left[ 1.2544 - 1 ight]$ $C.I. = 12500 	imes 0.2544$ $C.I. = 3180$ Thus, the compound interest is $Rs. 3180$.

What would be the $C.I.$ obtained on an amount of $12500$ at the rate of $12 \, p.c.p.a.$ after $2$ years (in $Rs.$)?

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