A man gave 50 % of his savings of ₹ 84,100 to | vedclass

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(A) Total savings $= ₹ 84,100$.Share given to wife $= 50 \% 	ext{ of } 84,100 = ₹ 42,050$.Remaining amount to be divided between sons $A$ and $B = ₹

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$20000$

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(A) Total savings $= ₹ 84,100$.Share given to wife $= 50 \% 	ext{ of } 84,100 = ₹ 42,050$.Remaining amount to be divided between sons $A$ and $B = ₹ 42,050$.Let the share of son $B$ be $x$. Then the share of son $A = 42,050 - x$.Son $A$ is $15$ years old,so he will attain $18$ years in $3$ years $(n_A = 3)$.Son $B$ is $13$ years old,so he will attain $18$ years in $5$ years $(n_B = 5)$.Rate of interest $r = 5 \%$.According to the problem,the amounts received by both at age $18$ are equal:$(42,050 - x) 	imes (1 + \frac{5}{100})^3 = x 	imes (1 + \frac{5}{100})^5$$(42,050 - x) = x 	imes (1 + \frac{5}{100})^2$$(42,050 - x) = x 	imes (1.05)^2$$42,050 - x = x 	imes 1.1025$$42,050 = 2.1025x$$x = \frac{42,050}{2.1025} = 20,000$.Thus,the share of $B$ is ₹ $20,000$.

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