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(C) Let the principal be $P$. The formula for compound interest $(CI)$ is given by $CI = P \left[ \left( 1 + \frac{R}{100} \right)^n - 1 \right]$.Give

Vedclass · Accepted Answer

$3200$

Vedclass · Answer

(C) Let the principal be $P$. The formula for compound interest $(CI)$ is given by $CI = P \left[ \left( 1 + \frac{R}{100} ight)^n - 1 ight]$.Given: $CI = 328$,$R = 5 \%$,and $n = 2$ years.Substituting the values into the formula:$328 = P \left[ \left( 1 + \frac{5}{100} ight)^2 - 1 ight]$$328 = P \left[ \left( \frac{105}{100} ight)^2 - 1 ight] = P \left[ \left( \frac{21}{20} ight)^2 - 1 ight]$$328 = P \left( \frac{441}{400} - 1 ight) = P \left( \frac{441 - 400}{400} ight) = P \left( \frac{41}{400} ight)$Solving for $P$:$P = \frac{328 	imes 400}{41}$$P = 8 	imes 400 = 3200$Thus,the sum is ₹ $3200$.

If the compound interest on a certain sum of money for $2$ years at $5 \%$ per annum is ₹ $328$,then the sum (in ₹) is:

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