What will be the minimum speed of the roller- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) At the highest point of the vertical circular path,the forces acting on the passenger are the gravitational force $mg$ (acting downwards) and the

Vedclass · Accepted Answer

$10$

Vedclass · Answer

(B) At the highest point of the vertical circular path,the forces acting on the passenger are the gravitational force $mg$ (acting downwards) and the normal reaction $N$ (acting downwards).The net centripetal force required for circular motion is provided by the sum of these forces:$N + mg = \frac{mv^2}{R}$For the passenger not to fall out,the minimum condition is that the normal reaction $N$ becomes zero at the top point.Setting $N = 0$,we get:$mg = \frac{mv^2}{R}$$v^2 = gR$$v = \sqrt{gR}$Given $g = 10 \ m \ s^{-2}$ and $R = 10 \ m$,we substitute these values:$v = \sqrt{10 	imes 10} = \sqrt{100} = 10 \ m \ s^{-1}$.Thus,the minimum speed required is $10 \ m \ s^{-1}$.

What will be the minimum speed of the roller-coaster so that the passenger at the top,when becomes upside down,does not fall out (in $m \ s^{-1}$)? Consider the acceleration due to gravity as $10 \ m \ s^{-2}$,and the radius of curvature of the roller coaster is $10 \ m$.

Similar Questions

The mass of the $bob$ of a simple pendulum of length $L$ is $m$. If the $bob$ is released from its horizontal position,then the speed of the $bob$ and the tension in the thread at the lowest position of the $bob$ will be respectively:

$A$ bucket tied at the end of a $1.6\, m$ long string is whirled in a vertical circle with constant speed. What should be the minimum speed so that the water from the bucket does not spill,when the bucket is at the highest position? (Take $g = 10\, m/s^2$)

If a particle completes a vertical circular motion,what is the ratio of its velocities at points $A$,$B$,and $C$?

$A$ stone of mass $1 \ kg$ is tied to a string $2 \ m$ long and is rotated at a constant speed of $40 \ ms^{-1}$ in a vertical circle. The ratio of the tension at the top and the bottom is [Take $g = 10 \ ms^{-2}$].

The maximum and minimum tension in the string whirling in a circle of radius $2.5 \, m$ with constant velocity are in the ratio $5 : 3$. Then its velocity is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module