The mass of the $bob$ of a simple pendulum of length $L$ is $m$. If the $bob$ is released from its horizontal position,then the speed of the $bob$ and the tension in the thread at the lowest position of the $bob$ will be respectively:

  • A
    $\sqrt{2gL}$ and $3mg$
  • B
    $3mg$ and $\sqrt{2gL}$
  • C
    $2mg$ and $\sqrt{2gL}$
  • D
    $2gL$ and $3mg$

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