What should be the length of a closed pipe to produce resonance with a sound wave of wavelength $62 \,cm$,in fundamental mode (in $\,cm$)? [Neglect end correction]

In the $5$th overtone of an open organ pipe,the number of nodes $(N)$ and antinodes $(A)$ are:

This question has Statement $1$ and Statement $2.$ Of the four choices given after the Statements,choose the one that best describes the two Statements.
Statement $1:$ In the resonance tube experiment,if the tuning fork is replaced by another identical tuning fork but with its arms filed,the length of the air column should be increased to obtain resonance again.
Statement $2:$ On filing the arms,the frequency of a tuning fork increases.

On producing waves of frequency $1000 \text{ Hz}$ in a Kundt's tube,the total distance between $6$ successive nodes is $85 \text{ cm}$. The speed of sound in the gas filled in the tube is ..... $m/s$.

In a closed organ pipe of length $105 \,cm$,standing waves are set up corresponding to the third overtone. What is the distance from the closed end where a pressure node is formed? (in $cm$)

When an open pipe is closed from one end, the third overtone of the closed pipe is higher in frequency by $150 \,Hz$ than the second overtone of the open pipe. The fundamental frequency of the open pipe will be: (in $\,Hz$)