In the 5th overtone of an open organ pipe,the | vedclass

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(B) For an open organ pipe,the frequency of the $n$th overtone is given by $f_n = (n+1)f_0$,where $f_0$ is the fundamental frequency.Thus,the $5$th ov

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$6N, 7A$

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(B) For an open organ pipe,the frequency of the $n$th overtone is given by $f_n = (n+1)f_0$,where $f_0$ is the fundamental frequency.Thus,the $5$th overtone corresponds to the $6$th harmonic mode ($n=5$,so harmonic number $p = n+1 = 6$).In an open organ pipe vibrating in the $p$th harmonic mode:Number of nodes $(N)$ = $p = 6$.Number of antinodes $(A)$ = $p + 1 = 6 + 1 = 7$.Therefore,there are $6$ nodes and $7$ antinodes.

In the $5$th overtone of an open organ pipe,the number of nodes $(N)$ and antinodes $(A)$ are:

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