On producing waves of frequency $1000 \text{ Hz}$ in a Kundt's tube,the total distance between $6$ successive nodes is $85 \text{ cm}$. The speed of sound in the gas filled in the tube is ..... $m/s$.
- A$330$
- B$340$
- C$350$
- D$300$
Explore More
Similar Questions
The first overtone frequency of an open organ pipe is equal to the fundamental frequency of a closed organ pipe. If the length of the closed organ pipe is $20 \, cm$,the length of the open organ pipe is ........ $cm$.
$A$ closed pipe and an open pipe have their first overtones identical in frequency. Their lengths are in the ratio:
Medium
View SolutionWhat kind of figures are possible for a closed pipe?
Medium
View SolutionAn air column in a pipe,which is closed at one end,will be in resonance with a vibrating body of frequency $166 \,Hz$,if the length of the air column is .... $m$. (Assume the speed of sound in air is $332 \,m/s$)
Easy
View Solution$A$ pipe open at both ends produces a fundamental frequency $n_1$. When the pipe is kept with $\frac{3}{4}$ of its length in water,it produces a note of fundamental frequency $n_2$. The ratio of $\frac{n_1}{n_2}$ is
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo