What are the position of centre of mass of symmetrical and homogeneous bodies?
What are the position of centre of mass of symmetrical and homogeneous bodies?
Similar Questions
The identical spheres each of mass $2 \mathrm{M}$ are placed at the corners of a right angled triangle with mutually perpendicular sides equal to $4 \mathrm{~m}$ each. Taking point of intersection of these two sides as origin, the magnitude of position vector of the centre of mass of the system is $\frac{4 \sqrt{2}}{x}$, where the value of $x$ is_____
The identical spheres each of mass $2 \mathrm{M}$ are placed at the corners of a right angled triangle with mutually perpendicular sides equal to $4 \mathrm{~m}$ each. Taking point of intersection of these two sides as origin, the magnitude of position vector of the centre of mass of the system is $\frac{4 \sqrt{2}}{x}$, where the value of $x$ is_____
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A thin uniform wire is bent to form the two equal sides $AB$ and $AC$ of triangle $ABC$, where $AB = AC = 5\,cm.$ The third side $BC$, of length $6\,cm,$ is made from uniform wire of twice the density of the first. The distance of centre of mass from $A$ is
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Three identical spheres each of mass $M$ are placed at the corners of a right angled triangle with mutually perpendicular sides equal to $3\,m$ each. Taking point of intersection of mutually perpendicular sides as origin, the magnitude of position vector of centre of mass of the system will be $\sqrt{x} m$. The value of $x$ is
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The position vector of three particles of masses $1\, kg, 2\, kg$ and $3\, kg$ are $\overrightarrow {{r_1}} = (\widehat i + 4\widehat j + \widehat k)\,m,\overrightarrow {{r_2}} = (\widehat i + \widehat j + \widehat k)\,m$ and $\overrightarrow {{r_3}} = (2\widehat i - \widehat j - 2\widehat k)\,m$ respectively. The position vector of their centre of mass is
The position vector of three particles of masses $1\, kg, 2\, kg$ and $3\, kg$ are $\overrightarrow {{r_1}} = (\widehat i + 4\widehat j + \widehat k)\,m,\overrightarrow {{r_2}} = (\widehat i + \widehat j + \widehat k)\,m$ and $\overrightarrow {{r_3}} = (2\widehat i - \widehat j - 2\widehat k)\,m$ respectively. The position vector of their centre of mass is