The identical spheres each of mass $2 \mathrm{M}$ are placed at the corners of a right angled triangle with mutually perpendicular sides equal to $4 \mathrm{~m}$ each. Taking point of intersection of these two sides as origin, the magnitude of position vector of the centre of mass of the system is $\frac{4 \sqrt{2}}{x}$, where the value of $x$ is_____
$2$
$3$
$4$
$5$
Obtain an expression for the position vector of centre of mass of a system n particles in two dimension.
A uniform disc of radius $R$ is put over another uniform disc of radius $2R$ made of same material having same thickness.The peripheries of the two discs touches each other.Locate the centre of mass of the system taking center center of large disc at origin
A uniform circular disc of radius $a$ is taken. A circular portion of radius $b$ has been removed from it as shown in the figure. If the centre of hole is at a distance $c$ from the centre of the disc, the distance $x_2$ of the centre of mass of the remaining part from the initial centre of mass $O$ is given by
Centre of mass of two thin uniform rods of same length but made up of different materials & kept as shown , can be, if the meeting point is the origin of co-ordinates
When does a body (system) have different centre of gravity and centre of mass ?