In the HCl molecule, the separation between t | vedclass

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Question

Let us choose the nucleus of the hydrogen atom as the origin for measuring distance.
Mass of hydrogen atom, $m_{1}=1$ unit (say) since cholorine atom

Vedclass · Accepted Answer

$1.24$

Vedclass · Answer

Let us choose the nucleus of the hydrogen atom as the origin for measuring distance.
Mass of hydrogen atom, $m_{1}=1$ unit (say) since cholorine atom is $35.5$ times as massive as hydrogen atom,
$	herefore$ mass of cholorine atom, $m_{2}=35.5$ units
Now, $x_{1}=0$ and $x_{2}=1.27 \mathrm{A}=1.27 	imes 10^{-16} \mathrm{m}$
Distance of centre of mass of HC1 molecule from the origin is given by
$X=\frac{m_{1} x_{1}+m_{2} x_{2}}{m_{1}+m_{2}}=\frac{1 	imes 0+35.5 	imes 1.27 	imes 10^{-10}}{1+35.5} m$
$=\frac{35.5 	imes 1.27}{36.5} 	imes 10^{-10} \mathrm{m}=1.235 	imes 10^{-10} \mathrm{m}=1.24 \mathrm{A}$

In the $HCl$ molecule, the separation between the nuclei of the two atoms is about $1.27\ \mathring A $. The approximate location of the centre of mass of the molecule from hydrogen is . ....... $\ \mathring A$. (assuming the chlorine atom to be about $35.5$ times massive as hydrogen)

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