Verify whether the following are zeroes of the polynomial, indicated against them.
$p(x) = (x + 1) (x -2)$, $x = -\,1, \,2$
Verify whether the following are zeroes of the polynomial, indicated against them.
$p(x) = (x + 1) (x -2)$, $x = -\,1, \,2$
If $x=-\,1$ and $x=2$ are zeroes of polynomial $p(x)=(x+1)(x-2),$ then $p(-1)$ and $p (2)$ should be $0$.
Here, $p (-1)=(-1+1)(-1-2)=0(-3)=0,$ and $p (2)$
$=(2+1)(2-2)=3(0)=0$
Therefore, $x=-1$ and $x=2$ are zeroes of the given polynomial.
Similar Questions
Write the coefficients of $x^2$ in each of the following :
$(i)$ $2+x^{2}+x $
$(ii)$ $2-x^{2}+x^{3}$
Write the coefficients of $x^2$ in each of the following :
$(i)$ $2+x^{2}+x $
$(ii)$ $2-x^{2}+x^{3}$
Determine which of the following polynomials has $(x + 1)$ a factor : $x^{3}+x^{2}+x+1$.
Determine which of the following polynomials has $(x + 1)$ a factor : $x^{3}+x^{2}+x+1$.
Factorise each of the following : $27 p^{3}-\frac{1}{216}-\frac{9}{2} p^{2}+\frac{1}{4} p$
Factorise each of the following : $27 p^{3}-\frac{1}{216}-\frac{9}{2} p^{2}+\frac{1}{4} p$
Verify whether the following are zeroes of the polynomial, indicated against them.
$p(x)=2 x+1, \,\,x=\frac{1}{2}$
Verify whether the following are zeroes of the polynomial, indicated against them.
$p(x)=2 x+1, \,\,x=\frac{1}{2}$
Factorise : $2 y^{3}+y^{2}-2 y-1$
Factorise : $2 y^{3}+y^{2}-2 y-1$