Verify whether the following are zeroes of the polynomial, indicated against them.

$p(x) = (x + 1) (x -2)$, $x = -\,1, \,2$

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If $x=-\,1$ and $x=2$ are zeroes of polynomial $p(x)=(x+1)(x-2),$ then $p(-1)$ and $p (2)$ should be $0$.

Here, $p (-1)=(-1+1)(-1-2)=0(-3)=0,$ and $p (2)$

$=(2+1)(2-2)=3(0)=0$

Therefore, $x=-1$ and $x=2$ are zeroes of the given polynomial.

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