One of the factors of left(25 x^{2}-1right)+( | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\left(25 x^{2}-1\right)+(1+5 x)^{2}=(5 x)^{2}-1^{2}+(5 x+1)^{2}$

$=(5 x-1)(5 x-1)+(5 x+1)^{2}=(5 x+1)(5 x-1+5 x+1)$

$=(5 x+1)(10 x)=10 x(5 x+1)

Vedclass · Accepted Answer

$10x$

Vedclass · Answer

$\left(25 x^{2}-1\right)+(1+5 x)^{2}=(5 x)^{2}-1^{2}+(5 x+1)^{2}$

$=(5 x-1)(5 x-1)+(5 x+1)^{2}=(5 x+1)(5 x-1+5 x+1)$

$=(5 x+1)(10 x)=10 x(5 x+1)$

Hence, one of the factors of $\left(25 x^{2}-1\right)+(1+5 x)^{2}$ is $10 x$.

Therefore, $(c)$ is the correct answer.

One of the factors of $\left(25 x^{2}-1\right)+(1+5 x)^{2}$ is

Similar Questions

The following expressions are polynomials? Justify your answer:

$\frac{1}{5 x^{-2}}+5 x+7$

Expand $:(3 x+7 y)(3 x-7 y)$

Which of the following expressions is a polynomial, state the reason ? If an expression is polynomial, state whether it is a polynomial in one variable or not

$x^{3}+3 x^{2} y+3 x y^{2}+y^{3}$

Classify the following as linear, quadratic or cubic polynomial

$x^{3}+5 x^{2}+12$

By acute division, find the quotient and the remainder when the first polynomial is divided by the second polynomial: $x^{4}+1 ; x+1$