Two planets have the same average density but their radii are ${R_1}$ and ${R_2}$. If acceleration due to gravity on these planets be ${g_1}$ and ${g_2}$ respectively, then
$\frac{{{g_1}}}{{{g_2}}} = \frac{{{R_1}}}{{{R_2}}}$
$\frac{{{g_1}}}{{{g_2}}} = \frac{{{R_2}}}{{{R_1}}}$
$\frac{{{g_1}}}{{{g_2}}} = \frac{{R_1^2}}{{R_2^2}}$
$\frac{{{g_1}}}{{{g_2}}} = \frac{{R_1^3}}{{R_2^3}}$
If the density of the earth is doubled keeping its radius constant, then acceleration due to gravity will be ........ $m/s^2$. $(g = 9.8\,m/sec^2)$
The variation of acceleration due to gravity $g$ with distance $d$ from centre of the earth is best represented by ($R =$ Earth's radius)
The acceleration due to gravity on a planet is $1.96 \,m / s ^2$. If it is safe to jump from a height of $3 \,m$ on the earth, the corresponding height on the planet will be ........ $m$
A body weighs $72\; N$ on the surface of the earth. What is the gravitational force on it, at a height equal to half the radius of the earth ?
The height of any point $P$ above the surface of earth is equal to diameter of earth. The value of acceleration due to gravity at point $P$ will be : (Given $g=$ acceleration due to gravity at the surface of earth)