If the density of the earth is doubled keepin | vedclass

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Question

$g=\left(G M / R^{2}ight)=\left(G / R^{2}ight) 	imes(4 / 3) \pi R^{3} 	imes ho=(4 / 3) \pi G R ho$

Radius is kept constant

$g \propto

Vedclass · Accepted Answer

$19.6$

Vedclass · Answer

$g=\left(G M / R^{2}ight)=\left(G / R^{2}ight) 	imes(4 / 3) \pi R^{3} 	imes ho=(4 / 3) \pi G R ho$

Radius is kept constant

$g \propto ho$

$g_{2}=g_{1}\left(ho_{2} / ho_{1}ight)$

Density is doubled hence $ho_{2}=2 ho_{1}$

$g_{2}=g_{1} 	imes 2$

$\mathrm{g}_{2}=19.6 \mathrm{m} / \mathrm{s}^{2}$

If the density of the earth is doubled keeping its radius constant, then acceleration due to gravity will be ........ $m/s^2$. $(g = 9.8\,m/sec^2)$

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