સામાન્ય બિંદુએ, l લંબાઇની દળરહિત દોરીઓ સાથે બ | vedclass

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Question

$	ext { From figure, } T \cos 	heta=m g.........(i)$

$T \sin 	heta=\frac{k q^{2}}{x^{2}}.........(ii)$

From eqns. $(i)$ and $(ii)$, $tan 	he

Vedclass · Accepted Answer

$v \propto {x^{ - \frac{1}{2}}}$

Vedclass · Answer

$	ext { From figure, } T \cos 	heta=m g.........(i)$

$T \sin 	heta=\frac{k q^{2}}{x^{2}}.........(ii)$

From eqns. $(i)$ and $(ii)$, $tan 	heta=\frac{k q^{2}}{x^{2} m g}$

since $	heta$ is small, $	herefore 	an 	heta  \approx \sin 	heta  = \frac{x}{{2l}}$

$	herefore \quad \frac{x}{2 l}=\frac{k q^{2}}{x^{2} m g} \Rightarrow q^{2}=x^{3} \frac{m g}{2 l k}$ or $q \propto x^{3 / 2}$

$\Rightarrow \frac{d q}{d t} \propto \frac{3}{2} \sqrt{x} \frac{d x}{d t}=\frac{3}{2} \sqrt{x} v$

since, $\frac{d q}{d t}=$ constant

$	herefore v \propto \frac{1}{\sqrt{x}}$

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