Two coaxial solenoids of different radii carry current $I$ in the same direction. Let $\;{\overrightarrow {\;F} _1}$ be the magnetic force on the inner solenoid due to the outer one and $\;{\overrightarrow {\;F} _2}$ be the magnetic force on the outer solenoid due to the inner one. Then
$\;\overrightarrow {{F_1}} $ is radially inwards and $\overrightarrow {{F_2}} $ is radially outwards
$\;\overrightarrow {{F_1}} $ is radially inwards and $\overrightarrow {\;{F_2}} $$=0$
$\overrightarrow {{F_1}} $ is radially outwards and $\overrightarrow {\;{F_2}} =0$
$\overrightarrow {{F_1}} =\overrightarrow {\;{F_2}} =0$
A non conducting ring (of mass $m,$ radius $r,$ having charge $Q$) is placed on a rough horizontal surface (in a region with transverse magnetic field). The field is increasing with time at the rate $R$ and coefficient of friction between the surface and the ring is $\mu .$ For ring to remain in equilibrium $\mu$ should be greater than
A circular coil of radius $4\, cm$ has $50$ $turns$. In this coil a current of $2\, A$ is flowing. It is placed in a magnetic field of $0.1$ $weber/{m^2}$. The amount of work done in rotating it through $180^\circ $ from its equilibrium position will be........$J$
Derive an expression for the force per unit length between two infinitely long straight parallel current carrying wires. Hence, define one ampere $( \mathrm{A} )$.
In figure shows three long straight wires $P, Q$ and $R$ carrying currents normal to the plane of the paper. All three currents have the same magnitude. Which arrow best shows the direction of the resultant force on the wire $P$
The resultant force on the current loop $PQRS$ due to a long current carrying conductor will be