Two billiard balls of equal mass $30 \,{g}$ strike a rigid wall with same speed of $108\, {kmph}$ (as shown) but at different angles. If the balls get reflected with the same speed then the ratio of the magnitude of impulses imparted to ball $'a'$ and ball $'b'$ by the wall along $'X'$ direction is :
$1: 1$
$\sqrt{2}: 1$
$1: \sqrt{2}$
$2: 1$
The linear momentum $p$ of a body moving in one dimension varies with time according to the equation $p = a + b{t^2}$ where a and b are positive constants. The net force acting on the body is
A body of mass $‘M’$ collides against a wall with a velocity $v$ and retraces its path with the same speed. The change in momentum is (take initial direction of velocity as positive)
A ball is thrown vertically up (taken as $+z-$ axis) from the ground. The correct momentum-height $(p-h)$ diagram is
Figure shows the position-time graph of a particle of mass $4 \,kg$. What is the
$(a)$ force on the particle for $t\, <\, 0, t \,> \,4\; s, 0 \,<\, t \,< \,4\; s$?
$(b)$ impulse at $t=0$ and $t=4 \;s ?$ (Consider one-dimensional motion only).
Below figure shows the position-time graph of a body of mass $0.04\; kg$. Suggest a suitable physical context for this motion. What is the time between two consecutive impulses received by the body ? What is the magnitude of each impulse ?