A ball is thrown vertically up (taken as +z- | vedclass

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Question

$\begin{array}{l}
Momentum\,p = mv\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...\left( 1 ight)\
and\,for\,motion\,under\,gra

Vedclass · Accepted Answer

Vedclass · Answer

$\begin{array}{l}
Momentum\,p = mv\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...\left( 1 ight)\
and\,for\,motion\,under\,gravity\,\
h = \frac{{{u^2} - {v^2}}}{{2g}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...\left( 2 ight)\
h = \frac{{{u^2} - {p^2}/m}}{{2g}}
\end{array}$

A ball is thrown vertically up (taken as $+z-$ axis) from the ground. The correct momentum-height $(p-h)$ diagram is

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