A body of mass $‘M’$ collides against a wall with a velocity $v$ and retraces its path with the same speed. The change in momentum is (take initial direction of velocity as positive)
$Zero$
$2Mv$
$Mv$
$-2\, Mv$
A ball of mass $150\,g$ starts moving with an acceleration of $20m/{s^2}$. When hit by a force, which acts on it for $0.1\, sec$. The impulsive force is ........ $N-s$
A particle of mass $m$ is moving in a straight line with momentum $p$. Starting at time $t = 0$, a force $F = kt$ acts in the same direction on the moving particle during time interval $T$ so that its momentum changes from $p$ to $3p$. Here $k$ is a constant. The value of $T$ is
Explain -product of mass and velocity is important in producing effect of force.
A ball is thrown vertically up (taken as $+z-$ axis) from the ground. The correct momentum-height $(p-h)$ diagram is
A girl riding a bicycle along a straight road with a speed of $5\,ms^{-1}$ throws a stone of mass $0.5\, kg$ which has a speed of $15\,ms^{-1}$ with respect to the ground along her direction of motion. The mass of the girl and bicycle is $ 50\, kg$. Does the speed of the bicycle change after the stone is thrown ? What is the change in speed, if so ?