Two billiard balls each of mass $0.05\; kg$ moving in opposite directions with speed $6\; m/s$ collide and rebound with the same speed. What is the impulse imparted to each ball due to the other (in $; Ns$)?

Five objects of different masses are simultaneously released vertically downwards from height $h$ (in air). Which physical quantity associated with the objects will change at the instant they strike the ground? (Neglect the air resistance.)

How can we draw a two-object $FBD$ (Free Body Diagram) according to Newton's third law?

$A$ ball of mass $0.5 \ kg$ moving horizontally at $10 \ m \ s^{-1}$ strikes a vertical wall and rebounds with speed $v$. The magnitude of the change in linear momentum is found to be $8.0 \ kg \ m \ s^{-1}$. The magnitude of $v$ is, (in $m \ s^{-1}$)

If the final momentum is equal to the initial momentum of the system,then:

$A$ bullet is fired from a gun. The force on the bullet is given by $F = 600 - 2 \times 10^5 t$,where $F$ is in newtons and $t$ is in seconds. The force on the bullet becomes zero as soon as it leaves the barrel. What is the impulse imparted to the bullet in $N-s$?