A soldier with a machine gun, falling from an | vedclass

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Question

(c)

In given case, rate of momentum change of bullets is equal to weight of soldier.

If $M=$ mass of soldier and his gun and $m=$ mass of bullet

Vedclass · Accepted Answer

$100$

Vedclass · Answer

(c)

In given case, rate of momentum change of bullets is equal to weight of soldier.

If $M=$ mass of soldier and his gun and $m=$ mass of bullet. Then,

$M g=\frac{N}{\Delta t} 	imes m(v-0)$

$\Rightarrow M =\frac{(N / \Delta t) 	imes m v}{g}$

where, $\frac{N}{\Delta t}$ is the number of bullets fired per second.

$\Rightarrow M =\frac{40 	imes 49 	imes 10^{-3} 	imes 500}{9.8}$

$=100 \,kg$

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