A small mass m is launched from the top of a | vedclass

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Question

$\mathrm{V} \cos 30^{\circ}=\mathrm{V}_{1} \cos 45^{\circ}$

$V\frac{{\sqrt 3 }}{2} = \frac{{{V_1}}}{{\sqrt 2 }}$

$\mathrm{J}=\mathrm{p}_{\mathrm

Vedclass · Accepted Answer

$\frac{1}{2}\left( {\sqrt 3  + 1} \right)\ mV$

Vedclass · Answer

$\mathrm{V} \cos 30^{\circ}=\mathrm{V}_{1} \cos 45^{\circ}$

$V\frac{{\sqrt 3 }}{2} = \frac{{{V_1}}}{{\sqrt 2 }}$

$\mathrm{J}=\mathrm{p}_{\mathrm{f}}-\mathrm{p}_{1}$

$=\mathrm{m}\left[-\mathrm{V}_{1} \sin 45^{\circ}-\mathrm{V} \sin 30^{\circ}ight]$

$=\mathrm{m}\left[-\mathrm{v} \sqrt{\frac{3}{2}} 	imes \frac{1}{\sqrt{2}}-\frac{\mathrm{V}}{2}ight]=\mathrm{m} \mathrm{V}\left[\frac{\sqrt{3}+1}{2}ight]$

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