Train A and train B are running on parallel t | vedclass

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(B) Let the direction of motion of train $A$ be positive $(+)$ and the direction of motion of train $B$ be negative $(-)$.Velocity of train $A$ $(V_A)

Vedclass · Accepted Answer

$29$

Vedclass · Answer

(B) Let the direction of motion of train $A$ be positive $(+)$ and the direction of motion of train $B$ be negative $(-)$.Velocity of train $A$ $(V_A)$ = $+36 \, km/h$.Velocity of train $B$ $(V_B)$ = $-72 \, km/h$.Velocity of the person with respect to train $A$ $(V_{m/A})$ = $-1.8 \, km/h$ (since the person is walking opposite to the motion of train $A$).Velocity of the person with respect to the ground $(V_m)$ = $V_{m/A} + V_A = -1.8 + 36 = 34.2 \, km/h$.Velocity of the person with respect to train $B$ $(V_{m/B})$ = $V_m - V_B = 34.2 - (-72) = 34.2 + 72 = 106.2 \, km/h$.To convert $km/h$ to $m/s$,multiply by $\frac{5}{18}$:$V_{m/B} = 106.2 	imes \frac{5}{18} = 5.9 	imes 5 = 29.5 \, m/s$.

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