There are two Vernier calipers both of which have $1 \mathrm{~cm}$ divided into $10$ equal divisions on the main scale. The Vernier scale of one of the calipers $\left(C_1\right)$ has $10$ squal divisions that correspond to $9$ main scale divisions. The Vernier scale of the other caliper $\left(C_2\right)$ has $10$ equal divisions that correspond to $11$ main scale divisions. The readings of the two calipers are shown in the figure. The measured values (in $\mathrm{cm}$ ) by calipers $C_1$ and $C_2$, respectively, are

222900-q

  • [IIT 2016]
  • A

    $2.85$ and $2.82$

  • B

    $2.87$ and $2.83$

  • C

    $2.87$ and $2.86$

  • D

    $2.87$ and $2.87$

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Diameter of a steel ball is measured using a Vernier callipers which has divisions of $0. 1\,cm$ on its main scale $(MS)$ and $10$ divisions of its vernier scale $(VS)$ match $9$ divisions on the main scale. Three such measurements for a ball are given as

    S.No.      $MS\;(cm)$ $VS$ divisions
   $(1)$      $0.5$       $8$
   $(2)$     $0.5$       $4$
   $(3)$     $0.5$       $6$

If the zero error is $- 0.03\,cm,$ then mean corrected diameter is  ........... $cm$

  • [JEE MAIN 2015]

Two full turns of the circular scale of screw gauge cover a distance of $1\,mm$ on scale. The total number of divisions on circular scale is $50$. Further, it is found that screw gauge has a zero error of $+0.03\,mm$. While measuring the diameter of a thin wire a student notes the main scale reading of $3\,mm$ and the number of circular scale division in line, with the main scale is $35$. The diameter of the wire is .......... $mm$