There are two urns. Urm A has 3 distinct red | vedclass

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Question

Total no. of balls in urn $\mathrm{A}=3$

Total no. of balls in urn $\mathrm{B}=9$

The number of ways in which two balls from urn $A$ and two bal

Vedclass · Accepted Answer

$108$

Vedclass · Answer

Total no. of balls in urn $\mathrm{A}=3$

Total no. of balls in urn $\mathrm{B}=9$

The number of ways in which two balls from urn $A$ and two balls from urn $B$ can be

selected $=3 C_{2} 	imes 9 C_{2}$

$3 C_{2}=\frac{3 !}{2 ! 1 !}=3$

$9 C_{2}=\frac{9 !}{2 ! 7 !}=\frac{9 	imes 8 	imes 7 !}{2 ! 	imes 7 !}=36$

$3 C_{2} 	imes 9 C_{2}=3 	imes 36$

$\Rightarrow 108$

There are two urns. Urm $A$ has $3$ distinct red balls and urn $B$ has $9$ distinct blue balls. From each urm two balls are taken out at random and then transferred to the other. The number of ways in which this can be done is

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