Out of 10 white,9 black and 7 red balls,the n | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The number of ways to select $0$ or more balls of a specific color is equal to the number of balls of that color plus $1$ (for the case of selecti

Vedclass · Accepted Answer

$879$

Vedclass · Answer

(C) The number of ways to select $0$ or more balls of a specific color is equal to the number of balls of that color plus $1$ (for the case of selecting none).For $10$ white balls,there are $(10 + 1) = 11$ ways.For $9$ black balls,there are $(9 + 1) = 10$ ways.For $7$ red balls,there are $(7 + 1) = 8$ ways.The total number of ways to select balls is $(11 	imes 10 	imes 8) = 880$.Since the question asks for the selection of one or more balls,we must exclude the case where no balls are selected (i.e.,$0$ balls of each color).Therefore,the required number of ways is $880 - 1 = 879$.

Out of $10$ white,$9$ black and $7$ red balls,the number of ways in which selection of one or more balls can be made,is

Similar Questions

$\binom{n}{r+1} + 2\binom{n}{r} + \binom{n}{r-1} = \dots$

In how many ways can $10$ balls be divided between two boys,such that one receives $2$ balls and the other receives $8$ balls?

The product of $r$ consecutive natural numbers is always divisible by......

There are $4$ oranges,$5$ apples,and $7$ mangoes in a fruit basket. The number of ways of selecting at least one fruit from among the fruits in the basket is

The number of four-digit numbers that can be formed using all the digits from $1$ to $9$ (excluding zero) such that every number has exactly $2$ distinct digits is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module