frac{{cot 54^circ }}{{tan 36^circ }} + frac{{ | vedclass

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Question

$	an (90^\circ  - 	heta ) = \cot 	heta ,\;\cot (90^\circ  - 	heta ) = 	an 	heta .$

इसलिए $\frac{{\cot 54^\circ }}{{	an 36^\circ }}

Vedclass · Accepted Answer

$2$

Vedclass · Answer

$	an (90^\circ  - 	heta ) = \cot 	heta ,\;\cot (90^\circ  - 	heta ) = 	an 	heta .$

इसलिए $\frac{{\cot 54^\circ }}{{	an 36^\circ }} + \frac{{	an 20^\circ }}{{\cot 70^\circ }}$

$ = \frac{{\cot 54^\circ }}{{	an (90^\circ  - 54^\circ )}} + \frac{{	an 20^\circ }}{{\cot (90^\circ  - 20^\circ )}}$

$= \frac{{\cot 54^\circ }}{{\cot 54^\circ }} + \frac{{	an 20^\circ }}{{	an 20^\circ }} = 1 + 1 = 2$.

$\frac{{\cot 54^\circ }}{{\tan 36^\circ }} + \frac{{\tan 20^\circ }}{{\cot 70^\circ }}$ का मान होगा

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