The value of frac{{cot 54^circ }}{{tan 36^cir | vedclass

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Question

(a) $	an (90^\circ - 	heta ) = \cot 	heta ,\;\cot (90^\circ - 	heta ) = 	an 	heta .$

Therefore $\frac{{\cot 54^\circ }}{{	an 36^\circ }} + \

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(a) $	an (90^\circ - 	heta ) = \cot 	heta ,\;\cot (90^\circ - 	heta ) = 	an 	heta .$

Therefore $\frac{{\cot 54^\circ }}{{	an 36^\circ }} + \frac{{	an 20^\circ }}{{\cot 70^\circ }}$ 

$ = \frac{{\cot 54^\circ }}{{	an (90^\circ - 54^\circ )}} + \frac{{	an 20^\circ }}{{(\cot 90^\circ - 20^\circ )}}$

$\frac{{\cot 54^\circ }}{{\cot 54^\circ }} + \frac{{	an 20^\circ }}{{	an 20^\circ }} = 1 + 1 = 2$.

The value of $\frac{{\cot 54^\circ }}{{\tan 36^\circ }} + \frac{{\tan 20^\circ }}{{\cot 70^\circ }}$ is

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