The value of frac{{cot 54^circ }}{{tan 36^cir | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(a) $	an (90^\circ - 	heta ) = \cot 	heta ,\;\cot (90^\circ - 	heta ) = 	an 	heta .$

Therefore $\frac{{\cot 54^\circ }}{{	an 36^\circ }} + \

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(a) $	an (90^\circ - 	heta ) = \cot 	heta ,\;\cot (90^\circ - 	heta ) = 	an 	heta .$

Therefore $\frac{{\cot 54^\circ }}{{	an 36^\circ }} + \frac{{	an 20^\circ }}{{\cot 70^\circ }}$ 

$ = \frac{{\cot 54^\circ }}{{	an (90^\circ - 54^\circ )}} + \frac{{	an 20^\circ }}{{(\cot 90^\circ - 20^\circ )}}$

$\frac{{\cot 54^\circ }}{{\cot 54^\circ }} + \frac{{	an 20^\circ }}{{	an 20^\circ }} = 1 + 1 = 2$.

The value of $\frac{{\cot 54^\circ }}{{\tan 36^\circ }} + \frac{{\tan 20^\circ }}{{\cot 70^\circ }}$ is

Similar Questions

If $\left| {\,a\,{{\sin }^2}\theta + b\sin \theta \cos \theta + c\,{{\cos }^2}\theta - \frac{1}{2}(a + c)\,} \right|\, \le \frac{1}{2}k,$ then ${k^2}$ is equal to

Prove that :

$\cot ^{2} \frac{\pi}{6}+\cos ec \,\frac{5 \pi}{6}+3 \tan ^{2}\, \frac{\pi}{6}=6$

The value of $2 \sin \left(12^{\circ}\right)-\sin \left(72^{\circ}\right)$ is

If $\sin (\alpha - \beta ) = \frac{1}{2}$ and $\cos (\alpha + \beta ) = \frac{1}{2},$ where $\alpha $ and $\beta $ are positive acute angles, then

If $\sin x=-\frac{3}{5}$, where $\pi < x < \frac{3 \pi}{2}$ then $80\left(\tan ^2 x-\cos x\right)$ is equal to :