The system of equations $x+3by+bz=0$,$x+2ay+az=0$ and $x+4cy+cz=0$ has

  • A
    only zero solution for any values of $a, b, c$
  • B
    non-zero solution for any values of $a, b, c$
  • C
    non-zero solution,whenever $b(a+c)=2ac$
  • D
    non-zero solution,whenever $a+c=2b$

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Let $A=\left[\begin{array}{lll}2 & 0 & 1 \\ 1 & 1 & 0 \\ 1 & 0 & 1\end{array}\right]$,$B=\left[B_1, B_2, B_3\right]$,where $B_1, B_2, B_3$ are column matrices,and $AB_1=\left[\begin{array}{l}1 \\ 0 \\ 0\end{array}\right]$,$AB_2=\left[\begin{array}{l}2 \\ 3 \\ 0\end{array}\right]$,$AB_3=\left[\begin{array}{l}3 \\ 2 \\ 1\end{array}\right]$. If $\alpha=|B|$ and $\beta$ is the sum of all the diagonal elements of $B$,then $\alpha^3+\beta^3$ is equal to

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