The sum of the bond orders of O_2^{2+}, O_2^{ | vedclass

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Question

(A) Using Molecular Orbital Theory $(MOT)$,the electronic configuration and properties are as follows:$O_2^{2+}$: Bond order = $3$,Unpaired electrons

Vedclass · Accepted Answer

$10, 4$

Vedclass · Answer

(A) Using Molecular Orbital Theory $(MOT)$,the electronic configuration and properties are as follows:$O_2^{2+}$: Bond order = $3$,Unpaired electrons = $0$$O_2^{2-}$: Bond order = $1$,Unpaired electrons = $0$$O_2^{+}$: Bond order = $2.5$,Unpaired electrons = $1$$O_2^{-}$: Bond order = $1.5$,Unpaired electrons = $1$$O_2$: Bond order = $2$,Unpaired electrons = $2$Sum of bond orders = $3 + 1 + 2.5 + 1.5 + 2 = 10$Sum of unpaired electrons = $0 + 0 + 1 + 1 + 2 = 4$Therefore,the correct answer is $10, 4$.

The sum of the bond orders of $O_2^{2+}, O_2^{2-}, O_2^{+}, O_2^{-}, O_2$ and the sum of the unpaired electrons present in them respectively are

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