Assuming that Hund's rule is violated,the bon | vedclass

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(A) The electronic configuration of $B_2$ ($10$ electrons) is $\sigma_{1s}^2 \sigma_{1s}^{*2} \sigma_{2s}^2 \sigma_{2s}^{*2} \pi_{2p_x}^2$.Bond order

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$1$ and diamagnetic

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(A) The electronic configuration of $B_2$ ($10$ electrons) is $\sigma_{1s}^2 \sigma_{1s}^{*2} \sigma_{2s}^2 \sigma_{2s}^{*2} \pi_{2p_x}^2$.Bond order is calculated as $\frac{	ext{Number of bonding electrons} - 	ext{Number of antibonding electrons}}{2}$.Bond order = $\frac{6 - 4}{2} = 1$.Since all electrons are paired in the $\pi_{2p_x}$ orbital under the assumption that Hund's rule is violated,the molecule is diamagnetic.

Assuming that Hund's rule is violated,the bond order and magnetic nature of the diatomic molecule $B_2$ is

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