Assuming that Hund's rule is violated, th | vedclass

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Question

$\mathrm{B}_2(10)=\sigma_{1 \mathrm{~s}^2} \sigma_{1 \mathrm{~s}^2}^* \sigma_{2 \mathrm{~s}^2} \sigma_{2 \mathrm{~s}^2}^* \pi_{2 \mathrm{p}_2^2}$

B

Vedclass · Accepted Answer

$1$ and diamagnetic

Vedclass · Answer

$\mathrm{B}_2(10)=\sigma_{1 \mathrm{~s}^2} \sigma_{1 \mathrm{~s}^2}^* \sigma_{2 \mathrm{~s}^2} \sigma_{2 \mathrm{~s}^2}^* \pi_{2 \mathrm{p}_2^2}$

Bond order $=\frac{6-4}{2}=1$

(nature diamagnetic as no unpaired electron)

Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule $B_2$ is

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