The bond order of a molecule is given by
The bond order of a molecule is given by
- A
The difference between the number of electrons in bonding and antibonding orbitals
- B
Total number of electrons in bonding and antibonding orbitals
- C
Twice the difference between the number of electrons in bonding and antibonding electrons
- D
Half the difference between the number of electrons in bonding and antibonding electrons
Similar Questions
The correct order of bond dissociation energy among $N_2, O_2, O_2^-$ is shown in which of the following arrangements?
The correct order of bond dissociation energy among $N_2, O_2, O_2^-$ is shown in which of the following arrangements?
- [JEE MAIN 2014]
Two pi and half sigma bonds are present in
Two pi and half sigma bonds are present in
- [JEE MAIN 2019]
Which of the following is paramagnetic ?
Which of the following is paramagnetic ?
- [NEET 2013]
The species having bond order different from that in $CO$ is
The species having bond order different from that in $CO$ is
Among $\mathrm{H}_2, \mathrm{He}_2^{+}, \mathrm{Li}_2, \mathrm{Be}_2, \mathrm{~B}_2, \mathrm{C}_2, \mathrm{~N}_2, \mathrm{O}_2^{-}$, and $\mathrm{F}_2$, the number of diamagnetic species is (Atomic numbers: $\mathrm{H}=1, \mathrm{He}=2, \mathrm{Li}=3, \mathrm{Be}=4, \mathrm{~B}=5, \mathrm{C}=6, \mathrm{~N}=7, \mathrm{O}=8, \mathrm{~F}=9$ )
Among $\mathrm{H}_2, \mathrm{He}_2^{+}, \mathrm{Li}_2, \mathrm{Be}_2, \mathrm{~B}_2, \mathrm{C}_2, \mathrm{~N}_2, \mathrm{O}_2^{-}$, and $\mathrm{F}_2$, the number of diamagnetic species is (Atomic numbers: $\mathrm{H}=1, \mathrm{He}=2, \mathrm{Li}=3, \mathrm{Be}=4, \mathrm{~B}=5, \mathrm{C}=6, \mathrm{~N}=7, \mathrm{O}=8, \mathrm{~F}=9$ )
- [IIT 2017]