If the bond order of CO is x,the bond order o | vedclass

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(C) The bond order of $CO$ is calculated as $3$,so $x = 3$. The electronic configuration of $O_2^{2-}$ is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \s

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$x / 3$

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(C) The bond order of $CO$ is calculated as $3$,so $x = 3$. The electronic configuration of $O_2^{2-}$ is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^2$. The number of bonding electrons $(N_b)$ is $10$ and the number of antibonding electrons $(N_a)$ is $8$. Bond order of $O_2^{2-} = \frac{1}{2}(N_b - N_a) = \frac{1}{2}(10 - 8) = 1$. Since $x = 3$,the bond order $1$ can be expressed as $x / 3$.

If the bond order of $CO$ is $x$,the bond order of $O_2^{2-}$ ion is

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