The sum of squares of deviations for 10 obser | vedclass

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(B) Given: Number of observations $n = 10$,Mean $\bar{x} = 50$,and sum of squares of deviations $\sum (x_i - \bar{x})^2 = 250$.First,calculate the var

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$10$

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(B) Given: Number of observations $n = 10$,Mean $\bar{x} = 50$,and sum of squares of deviations $\sum (x_i - \bar{x})^2 = 250$.First,calculate the variance $\sigma^2 = \frac{\sum (x_i - \bar{x})^2}{n} = \frac{250}{10} = 25$.Then,calculate the standard deviation $\sigma = \sqrt{25} = 5$.The coefficient of variation is given by the formula $CV = \left( \frac{\sigma}{\bar{x}} ight) 	imes 100$.Substituting the values,$CV = \left( \frac{5}{50} ight) 	imes 100 = 0.1 	imes 100 = 10\%$.

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$
Frequency	$2$	$3$	$x$	$5$	$4$

The sum of squares of deviations for $10$ observations taken from mean $50$ is $250$. The coefficient of variation is.....$\%$

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