The statement $( p \rightarrow( q \rightarrow p )) \rightarrow( p \rightarrow( p \vee q ))$ is
The statement $( p \rightarrow( q \rightarrow p )) \rightarrow( p \rightarrow( p \vee q ))$ is
- [JEE MAIN 2020]
- A
a contradiction
- B
equivalent to $( p \wedge q ) \vee(\sim q )$
- C
a tautology
- D
equivalent to $( p \vee q ) \wedge(\sim p )$
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