The slope of the graph as shown in the figure | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The slope of a curve at any point is given by the tangent of the angle $	heta$ that the tangent line at that point makes with the positive $x$-ax

Vedclass · Accepted Answer

$m_1 < m_2 < m_3$

Vedclass · Answer

(B) The slope of a curve at any point is given by the tangent of the angle $	heta$ that the tangent line at that point makes with the positive $x$-axis,i.e.,$m = 	an 	heta$.As we move along the curve from point $1$ to point $3$,the tangent line becomes steeper.This means the angle $	heta$ that the tangent makes with the positive $x$-axis increases as we move from point $1$ to point $3$ (i.e.,$	heta_1 Since the function $	an 	heta$ is an increasing function for $0^\circ Therefore,$m_1 < m_2 < m_3$.

The slope of the graph as shown in the figure at points $1, 2$ and $3$ is $m_1, m_2$ and $m_3$ respectively. Then:

Similar Questions

The value of $1+\frac{1}{4}+\frac{1}{16}+\frac{1}{64}+\ldots$ up to $\infty$ is

$\frac{d}{dx} \log(\log x) = $

$A$ particular straight line passes through the origin and a point whose abscissa is double the ordinate of the point. The equation of such a straight line is:

In the given figure,each box represents a function machine. $A$ function machine illustrates what it does with the input. Which of the following statements is correct?

The value of $\int\limits_0^{\frac{\pi }{{2\omega }}} {5\,\sin \omega t} \,dt$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module