The greatest value of the function -5, sin, t | vedclass

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Question

(B) The expression is of the form $a\, \sin\, 	heta + b\, \cos\, 	heta$,where $a = -5$ and $b = 12$.The maximum value of the function $f(	heta) = a

Vedclass · Accepted Answer

$13$

Vedclass · Answer

(B) The expression is of the form $a\, \sin\, 	heta + b\, \cos\, 	heta$,where $a = -5$ and $b = 12$.The maximum value of the function $f(	heta) = a\, \sin\, 	heta + b\, \cos\, 	heta$ is given by the formula $\sqrt{a^2 + b^2}$.Substituting the values,we get:Max value $= \sqrt{(-5)^2 + (12)^2}$Max value $= \sqrt{25 + 144}$Max value $= \sqrt{169}$Max value $= 13$.

The greatest value of the function $-5\, \sin\, \theta + 12\, \cos\, \theta$ is

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