The roots of the equation ${x^4} - 4{x^3} + 6{x^2} - 4x + 1 = 0$ are
The roots of the equation ${x^4} - 4{x^3} + 6{x^2} - 4x + 1 = 0$ are
- A
$1, 1, 1, 1$
- B
$2, 2, 2, 2$
- C
$3, 1, 3, 1$
- D
$1, 2, 1, 2$
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